MACD神馬版指標公式

① macd 公式

你說的是選股公式吧？可以啊，很簡單的。

在條件中加上：

diff>0.1;

-0.1到0.1之間的股票就給排除了

② 求這個MACD指標公式。要求通達信的!!

幫你寫一下啦：
DIF:EMA(CLOSE,12)-EMA(CLOSE,26);
DEA:EMA(DIF,9);
MACD:(DIF-DEA)*2,COLORSTICK;
上升版:IF(DIF>=REF(DIF,1),DIF,DRAWNULL),COLORRED;
下降權:IF(DIF<=REF(DIF,1),DIF,DRAWNULL),COLORGREEN;

③ 求高手作個MACD通達信指標公式，要求如下。

DIF:=EMA(CLOSE,12)-EMA(CLOSE,26);
DEA:=EMA(DIF,9);
MACD:=(DIF-DEA)*2;
XG:REF(MACD,2)>REF(MACD,1) AND MACD>REF(MACD,1) AND REF(MACD,1)>0;

測試通過!
希望能夠幫助你！

④ macd指標公式計算

你這個公式我試了好像畫不出來的。。

⑤ 請老師編個MACD指標公式

DIF:EMA(CLOSE,SHORT)-EMA(CLOSE,LONG);
DEA:EMA(DIF,MID);
MACD:(DIF-DEA)*2,COLORSTICK;
T:=BARSLAST(MACD>REF(MACD,1));
T0:=LLV(MACD,T+1)>0;
ZRXG:=REF(T>=2 AND T0,1) AND T=0;
DRAWICON(ZRXG,0,13);

⑥ 通達信MACD公式，請高手請把下面指標公式里的金叉死叉+個箭頭表示謝謝

DIFF:EMA(CLOSE,12)-EMA(CLOSE,26);
DEA:EMA(DIFF,9);
MACD:2*(DIFF-DEA), COLORSTICK,LINETHICK2;
低位金叉:=CROSS(DIFF,DEA) AND DIFF<-0.1;
STICKLINE(低位金叉,0,0.08,6,0),COLORYELLOW;
JCCOUNT:=COUNT(CROSS(DIFF,DEA),BARSLAST(DEA>=0));
二次金叉:=CROSS(DIFF,DEA) AND DEA<0 AND COUNT(JCCOUNT=2,21)=1;
STICKLINE(二次金叉,0,0.06,6,0),COLORFF00FF;
DRAWICON(二次金叉,DEA*0.9,1) ;
DRAWTEXT(二次金叉,0.1,' 二次金叉'),COLORYELLOW;
DRAWICON(CROSS(DIFF,DEA),DEA*1.02,1);
DRAWICON(CROSS(DEA,DIFF),DIFF*0.98,2);
A1:=BARSLAST(REF(CROSS(DIFF,DEA),1));
底背離:=REF(CLOSE,A1+1)>CLOSE AND DIFF>REF(DIFF,A1+1) AND CROSS(DIFF,DEA) AND DIFF<0;
STICKLINE(底背離,0,0.03,6,0),COLOR00FF00;
底背:DRAWLINE(A1=0,DEA,底背離,DEA,0),COLORRED,LINETHICK4;
DRAWTEXT(底背離,DIFF,' 底背離'),COLORFF00FF;
A2:=BARSLAST(REF(CROSS(DEA,DIFF),1));
頂背離:=REF(CLOSE,A2+1)<CLOSE AND REF(DIFF,A2+1)>DIFF AND CROSS(DEA,DIFF);
頂背:DRAWLINE(A2=0,DEA,頂背離,DEA,0),COLORGREEN,LINETHICK4;

⑦ 求通達信公式：macd選股公式

DIF:=EMA(CLOSE,12)-EMA(CLOSE,26);

DEA:=EMA(DIF,9);

MACD:=(DIF-DEA)*2;

X1:DIF>REF(DIF,1) AND V>=MA(V,50),COLORRED;

X2:MACD<REF(MACD,1),COLORGREEN;

這樣的條件設計會信號過多,而且,出現兩專條件重疊情況屬.